Compute lim_{x->0} sin(2x)/x.

Prepare for the DAY 2002A Limits Test with our targeted quiz. Test your understanding with flashcards and multiple-choice questions. Each question features hints and explanations to enhance your learning. Ace your exam!

Multiple Choice

Compute lim_{x->0} sin(2x)/x.

Explanation:
The key idea is the standard limit sin t / t → 1 as t → 0. Rewrite the expression as [sin(2x)/(2x)] · 2. As x → 0, 2x → 0, so sin(2x)/(2x) → 1, and the whole expression tends to 2. Equivalently, with u = 2x, you get sin(2x)/x = sin u /(u/2) = 2 · (sin u / u) → 2.

The key idea is the standard limit sin t / t → 1 as t → 0. Rewrite the expression as [sin(2x)/(2x)] · 2. As x → 0, 2x → 0, so sin(2x)/(2x) → 1, and the whole expression tends to 2. Equivalently, with u = 2x, you get sin(2x)/x = sin u /(u/2) = 2 · (sin u / u) → 2.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy