As x approaches 0 from the right, what is the limit of ln x?

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Multiple Choice

As x approaches 0 from the right, what is the limit of ln x?

Explanation:
As x gets arbitrarily close to zero from the right, ln x decreases without bound. Since ln is defined only for positive x and ln x is negative for x < 1, shrinking x toward 0 pushes the natural logarithm to more and more negative values. For example, ln(0.1) ≈ -2.302, ln(0.01) ≈ -4.605, and this trend continues without limit. A handy viewpoint is x = e^{-t} with t → ∞, giving ln x = ln(e^{-t}) = -t → -∞. So the limit is negative infinity.

As x gets arbitrarily close to zero from the right, ln x decreases without bound. Since ln is defined only for positive x and ln x is negative for x < 1, shrinking x toward 0 pushes the natural logarithm to more and more negative values. For example, ln(0.1) ≈ -2.302, ln(0.01) ≈ -4.605, and this trend continues without limit. A handy viewpoint is x = e^{-t} with t → ∞, giving ln x = ln(e^{-t}) = -t → -∞. So the limit is negative infinity.

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